Base | Representation |
---|---|
bin | 10011001111100101010… |
… | …011100000001110001011 |
3 | 11200102100110202202112210 |
4 | 103033211103200032023 |
5 | 133131234411230201 |
6 | 2451300401240203 |
7 | 164353233001260 |
oct | 23174523401613 |
9 | 4612313682483 |
10 | 1322402055051 |
11 | 46a911537780 |
12 | 194359933063 |
13 | 9791832a20c |
14 | 4800c8a7267 |
15 | 245ea9c11d6 |
hex | 133e54e038b |
1322402055051 has 32 divisors (see below), whose sum is σ = 2199698496000. Its totient is φ = 686518433280.
The previous prime is 1322402054951. The next prime is 1322402055127. The reversal of 1322402055051 is 1505502042231.
It is not a de Polignac number, because 1322402055051 - 217 = 1322401923979 is a prime.
It is a super-2 number, since 2×13224020550512 (a number of 25 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (1322402057051) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 1490046 + ... + 2205683.
It is an arithmetic number, because the mean of its divisors is an integer number (68740578000).
Almost surely, 21322402055051 is an apocalyptic number.
1322402055051 is a gapful number since it is divisible by the number (11) formed by its first and last digit.
1322402055051 is a deficient number, since it is larger than the sum of its proper divisors (877296440949).
1322402055051 is a wasteful number, since it uses less digits than its factorization.
1322402055051 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3697299.
The product of its (nonzero) digits is 12000, while the sum is 30.
Adding to 1322402055051 its reverse (1505502042231), we get a palindrome (2827904097282).
The spelling of 1322402055051 in words is "one trillion, three hundred twenty-two billion, four hundred two million, fifty-five thousand, fifty-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.082 sec. • engine limits •