Base | Representation |
---|---|
bin | 111101100101000111… |
… | …1101000001110001001 |
3 | 110122100011212102000111 |
4 | 1323022033220032021 |
5 | 4131312440112132 |
6 | 140430131234321 |
7 | 12361040263111 |
oct | 1731217501611 |
9 | 418304772014 |
10 | 132242113417 |
11 | 510a1253127 |
12 | 217677489a1 |
13 | c61655c96b |
14 | 658718a041 |
15 | 368eaed647 |
hex | 1eca3e8389 |
132242113417 has 2 divisors, whose sum is σ = 132242113418. Its totient is φ = 132242113416.
The previous prime is 132242113411. The next prime is 132242113453. The reversal of 132242113417 is 714311242231.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 79196653561 + 53045459856 = 281419^2 + 230316^2 .
It is a cyclic number.
It is not a de Polignac number, because 132242113417 - 235 = 97882375049 is a prime.
It is not a weakly prime, because it can be changed into another prime (132242113411) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66121056708 + 66121056709.
It is an arithmetic number, because the mean of its divisors is an integer number (66121056709).
Almost surely, 2132242113417 is an apocalyptic number.
It is an amenable number.
132242113417 is a deficient number, since it is larger than the sum of its proper divisors (1).
132242113417 is an equidigital number, since it uses as much as digits as its factorization.
132242113417 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 8064, while the sum is 31.
Adding to 132242113417 its reverse (714311242231), we get a palindrome (846553355648).
The spelling of 132242113417 in words is "one hundred thirty-two billion, two hundred forty-two million, one hundred thirteen thousand, four hundred seventeen".
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