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13224333433 is a prime number
BaseRepresentation
bin11000101000011101…
…10101000001111001
31021010121220202002011
430110032311001321
5204040412132213
610024123205521
7645465656653
oct142416650171
937117822064
1013224333433
115676878493
1226909768a1
1313299c898c
148d64836d3
15525eb603d
hex3143b5079

13224333433 has 2 divisors, whose sum is σ = 13224333434. Its totient is φ = 13224333432.

The previous prime is 13224333427. The next prime is 13224333457. The reversal of 13224333433 is 33433342231.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 12953171344 + 271162089 = 113812^2 + 16467^2 .

It is an emirp because it is prime and its reverse (33433342231) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 13224333433 - 25 = 13224333401 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 13224333395 and 13224333404.

It is not a weakly prime, because it can be changed into another prime (13224333403) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6612166716 + 6612166717.

It is an arithmetic number, because the mean of its divisors is an integer number (6612166717).

Almost surely, 213224333433 is an apocalyptic number.

It is an amenable number.

13224333433 is a deficient number, since it is larger than the sum of its proper divisors (1).

13224333433 is an equidigital number, since it uses as much as digits as its factorization.

13224333433 is an evil number, because the sum of its binary digits is even.

The product of its digits is 46656, while the sum is 31.

Adding to 13224333433 its reverse (33433342231), we get a palindrome (46657675664).

The spelling of 13224333433 in words is "thirteen billion, two hundred twenty-four million, three hundred thirty-three thousand, four hundred thirty-three".