Base | Representation |
---|---|
bin | 11110000100100000101011… |
… | …000011010001011010111011 |
3 | 122100021002212100010011021121 |
4 | 132010200223003101122323 |
5 | 114313301233421202012 |
6 | 1145135233414250111 |
7 | 36566562604506454 |
oct | 3604405303213273 |
9 | 570232770104247 |
10 | 132251355256507 |
11 | 39159537290563 |
12 | 129bb247356937 |
13 | 58a43318bc266 |
14 | 2492ddd44612b |
15 | 1045264347a07 |
hex | 78482b0d16bb |
132251355256507 has 2 divisors, whose sum is σ = 132251355256508. Its totient is φ = 132251355256506.
The previous prime is 132251355256483. The next prime is 132251355256571. The reversal of 132251355256507 is 705652553152231.
It is a weak prime.
It is an emirp because it is prime and its reverse (705652553152231) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 132251355256507 - 215 = 132251355223739 is a prime.
It is not a weakly prime, because it can be changed into another prime (132251355251507) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66125677628253 + 66125677628254.
It is an arithmetic number, because the mean of its divisors is an integer number (66125677628254).
Almost surely, 2132251355256507 is an apocalyptic number.
132251355256507 is a deficient number, since it is larger than the sum of its proper divisors (1).
132251355256507 is an equidigital number, since it uses as much as digits as its factorization.
132251355256507 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 9450000, while the sum is 52.
The spelling of 132251355256507 in words is "one hundred thirty-two trillion, two hundred fifty-one billion, three hundred fifty-five million, two hundred fifty-six thousand, five hundred seven".
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