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132251513256433 is a prime number
BaseRepresentation
bin11110000100100000110100…
…011101111111100111110001
3122100021010021100102101102201
4132010200310131333213301
5114313302044343201213
61145135301220543201
736566566533465604
oct3604406435774761
9570233240371381
10132251513256433
113915960849720a
12129bb290251b01
1358a435855c53c
14249301641433b
1510452731576dd
hex78483477f9f1

132251513256433 has 2 divisors, whose sum is σ = 132251513256434. Its totient is φ = 132251513256432.

The previous prime is 132251513256419. The next prime is 132251513256451. The reversal of 132251513256433 is 334652315152231.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 127549173050289 + 4702340206144 = 11293767^2 + 2168488^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-132251513256433 is a prime.

It is not a weakly prime, because it can be changed into another prime (132251513256133) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66125756628216 + 66125756628217.

It is an arithmetic number, because the mean of its divisors is an integer number (66125756628217).

Almost surely, 2132251513256433 is an apocalyptic number.

It is an amenable number.

132251513256433 is a deficient number, since it is larger than the sum of its proper divisors (1).

132251513256433 is an equidigital number, since it uses as much as digits as its factorization.

132251513256433 is an evil number, because the sum of its binary digits is even.

The product of its digits is 1944000, while the sum is 46.

The spelling of 132251513256433 in words is "one hundred thirty-two trillion, two hundred fifty-one billion, five hundred thirteen million, two hundred fifty-six thousand, four hundred thirty-three".