Base | Representation |
---|---|
bin | 11110000100100000110101… |
… | …001001000111010100000100 |
3 | 122100021010022010200200012020 |
4 | 132010200311021013110010 |
5 | 114313302110241411012 |
6 | 1145135302303123140 |
7 | 36566600031535155 |
oct | 3604406511072404 |
9 | 570233263620166 |
10 | 132251524560132 |
11 | 3915961390790a |
12 | 129bb293ba34b0 |
13 | 58a435a9b9613 |
14 | 2493017b1792c |
15 | 104527413ba8c |
hex | 784835247504 |
132251524560132 has 12 divisors (see below), whose sum is σ = 308586890640336. Its totient is φ = 44083841520040.
The previous prime is 132251524560061. The next prime is 132251524560151. The reversal of 132251524560132 is 231065425152231.
It is a tau number, because it is divible by the number of its divisors (12).
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5510480189994 + ... + 5510480190017.
It is an arithmetic number, because the mean of its divisors is an integer number (25715574220028).
Almost surely, 2132251524560132 is an apocalyptic number.
132251524560132 is a gapful number since it is divisible by the number (12) formed by its first and last digit.
It is an amenable number.
132251524560132 is an abundant number, since it is smaller than the sum of its proper divisors (176335366080204).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
132251524560132 is a wasteful number, since it uses less digits than its factorization.
132251524560132 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 11020960380018 (or 11020960380016 counting only the distinct ones).
The product of its (nonzero) digits is 432000, while the sum is 42.
The spelling of 132251524560132 in words is "one hundred thirty-two trillion, two hundred fifty-one billion, five hundred twenty-four million, five hundred sixty thousand, one hundred thirty-two".
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