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132254503054001 is a prime number
BaseRepresentation
bin11110000100100011100110…
…101011001010101010110001
3122100021101222201020211122222
4132010203212223022222301
5114313324210240212001
61145140514022410425
736600033606366566
oct3604434653125261
9570241881224588
10132254503054001
113915a902119399
12129bb985590a15
1358a4713ab1023
14249321b52286d
15104539a88361b
hex7848e6acaab1

132254503054001 has 2 divisors, whose sum is σ = 132254503054002. Its totient is φ = 132254503054000.

The previous prime is 132254503053997. The next prime is 132254503054033. The reversal of 132254503054001 is 100450305452231.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 103566952936225 + 28687550117776 = 10176785^2 + 5356076^2 .

It is a cyclic number.

It is not a de Polignac number, because 132254503054001 - 22 = 132254503053997 is a prime.

It is a Sophie Germain prime.

It is a Curzon number.

It is not a weakly prime, because it can be changed into another prime (132254503054501) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66127251527000 + 66127251527001.

It is an arithmetic number, because the mean of its divisors is an integer number (66127251527001).

Almost surely, 2132254503054001 is an apocalyptic number.

It is an amenable number.

132254503054001 is a deficient number, since it is larger than the sum of its proper divisors (1).

132254503054001 is an equidigital number, since it uses as much as digits as its factorization.

132254503054001 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 72000, while the sum is 35.

The spelling of 132254503054001 in words is "one hundred thirty-two trillion, two hundred fifty-four billion, five hundred three million, fifty-four thousand, one".