Base | Representation |
---|---|
bin | 11110000100100101010011… |
… | …110001000011101000000101 |
3 | 122100021120201021012201011021 |
4 | 132010211103301003220011 |
5 | 114313341432312031230 |
6 | 1145141415403311141 |
7 | 36600130142346325 |
oct | 3604452361035005 |
9 | 570246637181137 |
10 | 132256333314565 |
11 | 39160661271229 |
12 | 12a001b651b4b1 |
13 | 58a4946037845 |
14 | 2493352635285 |
15 | 10454563b7c7a |
hex | 784953c43a05 |
132256333314565 has 32 divisors (see below), whose sum is σ = 168266249424000. Its totient is φ = 99513040313088.
The previous prime is 132256333314533. The next prime is 132256333314571. The reversal of 132256333314565 is 565413333652231.
It is a cyclic number.
It is not a de Polignac number, because 132256333314565 - 25 = 132256333314533 is a prime.
It is a super-2 number, since 2×1322563333145652 (a number of 29 digits) contains 22 as substring.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 824928631 + ... + 825088939.
It is an arithmetic number, because the mean of its divisors is an integer number (5258320294500).
Almost surely, 2132256333314565 is an apocalyptic number.
It is an amenable number.
132256333314565 is a deficient number, since it is larger than the sum of its proper divisors (36009916109435).
132256333314565 is a wasteful number, since it uses less digits than its factorization.
132256333314565 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 222949.
The product of its digits is 17496000, while the sum is 52.
Adding to 132256333314565 its reverse (565413333652231), we get a palindrome (697669666966796).
The spelling of 132256333314565 in words is "one hundred thirty-two trillion, two hundred fifty-six billion, three hundred thirty-three million, three hundred fourteen thousand, five hundred sixty-five".
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