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132256654052521 is a prime number
BaseRepresentation
bin11110000100100101100110…
…111000100100110010101001
3122100021121112121201212220211
4132010211212320210302221
5114313343111414140041
61145141511302021121
736600141115520365
oct3604454670446251
9570247477655824
10132256654052521
113916080631a419
1212a00285a177a1
1358a499761690b
1424933830862a5
151045474621481
hex784966e24ca9

132256654052521 has 2 divisors, whose sum is σ = 132256654052522. Its totient is φ = 132256654052520.

The previous prime is 132256654052447. The next prime is 132256654052531. The reversal of 132256654052521 is 125250456652231.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 110087519907600 + 22169134144921 = 10492260^2 + 4708411^2 .

It is a cyclic number.

It is not a de Polignac number, because 132256654052521 - 215 = 132256654019753 is a prime.

It is not a weakly prime, because it can be changed into another prime (132256654052531) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66128327026260 + 66128327026261.

It is an arithmetic number, because the mean of its divisors is an integer number (66128327026261).

Almost surely, 2132256654052521 is an apocalyptic number.

It is an amenable number.

132256654052521 is a deficient number, since it is larger than the sum of its proper divisors (1).

132256654052521 is an equidigital number, since it uses as much as digits as its factorization.

132256654052521 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 4320000, while the sum is 49.

The spelling of 132256654052521 in words is "one hundred thirty-two trillion, two hundred fifty-six billion, six hundred fifty-four million, fifty-two thousand, five hundred twenty-one".