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132260135612500 = 225573121572887
BaseRepresentation
bin11110000100101000110110…
…011001101011000001010100
3122100021221112020220110100201
4132010220312121223001110
5114313422224204100000
61145143244551550244
736600323312346130
oct3604506631530124
9570257466813321
10132260135612500
11391622325a1a15
1212a00a9798b384
1358a51009c7b8c
1424935d36043c0
1510455ca0d996a
hex784a3666b054

132260135612500 has 216 divisors, whose sum is σ = 341638898961024. Its totient is φ = 43883519400000.

The previous prime is 132260135612477. The next prime is 132260135612513. The reversal of 132260135612500 is 5216531062231.

132260135612500 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It is a self number, because there is not a number n which added to its sum of digits gives 132260135612500.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 71 ways as a sum of consecutive naturals, for example, 83301057 + ... + 84873943.

It is an arithmetic number, because the mean of its divisors is an integer number (1581661569264).

Almost surely, 2132260135612500 is an apocalyptic number.

132260135612500 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 132260135612500, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (170819449480512).

132260135612500 is an abundant number, since it is smaller than the sum of its proper divisors (209378763348524).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

132260135612500 is an equidigital number, since it uses as much as digits as its factorization.

132260135612500 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1572985 (or 1572932 counting only the distinct ones).

The product of its (nonzero) digits is 64800, while the sum is 37.

Adding to 132260135612500 its reverse (5216531062231), we get a palindrome (137476666674731).

The spelling of 132260135612500 in words is "one hundred thirty-two trillion, two hundred sixty billion, one hundred thirty-five million, six hundred twelve thousand, five hundred".