Base | Representation |
---|---|
bin | 10011010000001000111… |
… | …100111010010000101011 |
3 | 11200110220011010012200111 |
4 | 103100020330322100223 |
5 | 133134001012042141 |
6 | 2451440003515151 |
7 | 164404114256113 |
oct | 23201074722053 |
9 | 4613804105614 |
10 | 1323000112171 |
11 | 470099088961 |
12 | 1944a6088ab7 |
13 | 979b21c567a |
14 | 480680a6043 |
15 | 24633258381 |
hex | 13408f3a42b |
1323000112171 has 2 divisors, whose sum is σ = 1323000112172. Its totient is φ = 1323000112170.
The previous prime is 1323000112139. The next prime is 1323000112219. The reversal of 1323000112171 is 1712110003231.
It is a weak prime.
It is an emirp because it is prime and its reverse (1712110003231) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1323000112171 - 25 = 1323000112139 is a prime.
It is not a weakly prime, because it can be changed into another prime (1323000116171) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 661500056085 + 661500056086.
It is an arithmetic number, because the mean of its divisors is an integer number (661500056086).
Almost surely, 21323000112171 is an apocalyptic number.
1323000112171 is a deficient number, since it is larger than the sum of its proper divisors (1).
1323000112171 is an equidigital number, since it uses as much as digits as its factorization.
1323000112171 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 252, while the sum is 22.
The spelling of 1323000112171 in words is "one trillion, three hundred twenty-three billion, one hundred twelve thousand, one hundred seventy-one".
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