Base | Representation |
---|---|
bin | 11110000101001110111011… |
… | …010011010100001001010101 |
3 | 122100102212001120010121200220 |
4 | 132011032323103110021111 |
5 | 114320104442111140313 |
6 | 1145214125522424553 |
7 | 36603301416161262 |
oct | 3605167323241125 |
9 | 570385046117626 |
10 | 132301020021333 |
11 | 391786027a3449 |
12 | 12a089a7b02159 |
13 | 58a8c18075377 |
14 | 2495591430269 |
15 | 10466be56d823 |
hex | 7853bb4d4255 |
132301020021333 has 8 divisors (see below), whose sum is σ = 176441242786368. Its totient is φ = 88180738635264.
The previous prime is 132301020021323. The next prime is 132301020021367. The reversal of 132301020021333 is 333120020103231.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 132301020021333 - 217 = 132301019890261 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (132301020021323) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 4985329260 + ... + 4985355797.
It is an arithmetic number, because the mean of its divisors is an integer number (22055155348296).
Almost surely, 2132301020021333 is an apocalyptic number.
It is an amenable number.
132301020021333 is a deficient number, since it is larger than the sum of its proper divisors (44140222765035).
132301020021333 is an equidigital number, since it uses as much as digits as its factorization.
132301020021333 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 9970689483.
The product of its (nonzero) digits is 1944, while the sum is 24.
Adding to 132301020021333 its reverse (333120020103231), we get a palindrome (465421040124564).
The spelling of 132301020021333 in words is "one hundred thirty-two trillion, three hundred one billion, twenty million, twenty-one thousand, three hundred thirty-three".
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