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13230113101 = 115111494451
BaseRepresentation
bin11000101001001001…
…11000000101001101
31021011000210101021221
430110210320011031
5204043402104401
610024451123341
7645566051212
oct142444700515
937130711257
1013230113101
11567a065877
1226928a3551
13132ac705ba
148d7149b09
155267587a1
hex31493814d

13230113101 has 4 divisors (see below), whose sum is σ = 13241608704. Its totient is φ = 13218617500.

The previous prime is 13230113089. The next prime is 13230113129. The reversal of 13230113101 is 10131103231.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 13230113101 - 215 = 13230080333 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13230113191) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5746075 + ... + 5748376.

It is an arithmetic number, because the mean of its divisors is an integer number (3310402176).

Almost surely, 213230113101 is an apocalyptic number.

It is an amenable number.

13230113101 is a deficient number, since it is larger than the sum of its proper divisors (11495603).

13230113101 is a wasteful number, since it uses less digits than its factorization.

13230113101 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 11495602.

The product of its (nonzero) digits is 54, while the sum is 16.

Adding to 13230113101 its reverse (10131103231), we get a palindrome (23361216332).

The spelling of 13230113101 in words is "thirteen billion, two hundred thirty million, one hundred thirteen thousand, one hundred one".

Divisors: 1 1151 11494451 13230113101