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13230113100 = 22352611037019
BaseRepresentation
bin11000101001001001…
…11000000101001100
31021011000210101021220
430110210320011030
5204043402104400
610024451123340
7645566051211
oct142444700514
937130711256
1013230113100
11567a065876
1226928a3550
13132ac705b9
148d7149b08
155267587a0
hex31493814c

13230113100 has 144 divisors (see below), whose sum is σ = 39289985280. Its totient is φ = 3436012800.

The previous prime is 13230113089. The next prime is 13230113129. The reversal of 13230113100 is 131103231.

It is a super-2 number, since 2×132301131002 (a number of 21 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (15).

It is a self number, because there is not a number n which added to its sum of digits gives 13230113100.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 1881391 + ... + 1888409.

It is an arithmetic number, because the mean of its divisors is an integer number (272847120).

Almost surely, 213230113100 is an apocalyptic number.

13230113100 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 13230113100, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (19644992640).

13230113100 is an abundant number, since it is smaller than the sum of its proper divisors (26059872180).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13230113100 is a wasteful number, since it uses less digits than its factorization.

13230113100 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 7200 (or 7193 counting only the distinct ones).

The product of its (nonzero) digits is 54, while the sum is 15.

Adding to 13230113100 its reverse (131103231), we get a palindrome (13361216331).

The spelling of 13230113100 in words is "thirteen billion, two hundred thirty million, one hundred thirteen thousand, one hundred".

Divisors: 1 2 3 4 5 6 10 12 15 20 25 30 50 60 61 75 100 103 122 150 183 206 244 300 305 309 366 412 515 610 618 732 915 1030 1220 1236 1525 1545 1830 2060 2575 3050 3090 3660 4575 5150 6100 6180 6283 7019 7725 9150 10300 12566 14038 15450 18300 18849 21057 25132 28076 30900 31415 35095 37698 42114 62830 70190 75396 84228 94245 105285 125660 140380 157075 175475 188490 210570 314150 350950 376980 421140 428159 471225 526425 628300 701900 722957 856318 942450 1052850 1284477 1445914 1712636 1884900 2105700 2140795 2168871 2568954 2891828 3614785 4281590 4337742 5137908 6422385 7229570 8563180 8675484 10703975 10844355 12844770 14459140 18073925 21407950 21688710 25689540 32111925 36147850 42815900 43377420 44100377 54221775 64223850 72295700 88200754 108443550 128447700 132301131 176401508 216887100 220501885 264602262 441003770 529204524 661505655 882007540 1102509425 1323011310 2205018850 2646022620 3307528275 4410037700 6615056550 13230113100