1323012123141 has 4 divisors (see below), whose sum is σ = 1764016164192. Its totient is φ = 882008082092.

The previous prime is 1323012123137. The next prime is 1323012123149. The reversal of 1323012123141 is 1413212103231.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1323012123141 - 2² = 1323012123137 is a prime.

It is a super-2 number, since 2×1323012123141² (a number of 25 digits) contains 22 as substring.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1323012123149) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 220502020521 + ... + 220502020526.

It is an arithmetic number, because the mean of its divisors is an integer number (441004041048).

Almost surely, 2^{1323012123141} is an apocalyptic number.

It is an amenable number.

1323012123141 is a deficient number, since it is larger than the sum of its proper divisors (441004041051).

1323012123141 is an equidigital number, since it uses as much as digits as its factorization.

1323012123141 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 441004041050.

The product of its (nonzero) digits is 864, while the sum is 24.

Adding to 1323012123141 its reverse (1413212103231), we get a palindrome (2736224226372).

The spelling of 1323012123141 in words is "one trillion, three hundred twenty-three billion, twelve million, one hundred twenty-three thousand, one hundred forty-one".