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13230154051 = 73181234987
BaseRepresentation
bin11000101001001010…
…00010000101000011
31021011000212110110121
430110211002011003
5204043404412201
610024452041111
7645566311462
oct142445020503
937130773417
1013230154051
11567a093614
122692903197
13132ac8612a
148d715a9d9
155267659a1
hex314942143

13230154051 has 4 divisors (see below), whose sum is σ = 13411389112. Its totient is φ = 13048918992.

The previous prime is 13230154039. The next prime is 13230154057. The reversal of 13230154051 is 15045103231.

It is a happy number.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 13230154051 - 211 = 13230152003 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13230154057) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 90617421 + ... + 90617566.

It is an arithmetic number, because the mean of its divisors is an integer number (3352847278).

Almost surely, 213230154051 is an apocalyptic number.

13230154051 is a deficient number, since it is larger than the sum of its proper divisors (181235061).

13230154051 is an equidigital number, since it uses as much as digits as its factorization.

13230154051 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 181235060.

The product of its (nonzero) digits is 1800, while the sum is 25.

Adding to 13230154051 its reverse (15045103231), we get a palindrome (28275257282).

It can be divided in two parts, 13230 and 154051, that added together give a square (167281 = 4092).

The spelling of 13230154051 in words is "thirteen billion, two hundred thirty million, one hundred fifty-four thousand, fifty-one".

Divisors: 1 73 181234987 13230154051