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132302303131241 is a prime number
BaseRepresentation
bin11110000101010000000111…
…110001111111011001101001
3122100102222100222112100121002
4132011100013301333121221
5114320120104100144431
61145214501120124345
736603345256344425
oct3605200761773151
9570388328470532
10132302303131241
1139179101004961
1212a090a57666b5
1358a9090b485b9
1424956739d5b85
1510467470243cb
hex785407c7f669

132302303131241 has 2 divisors, whose sum is σ = 132302303131242. Its totient is φ = 132302303131240.

The previous prime is 132302303131213. The next prime is 132302303131267. The reversal of 132302303131241 is 142131303203231.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 104265235771225 + 28037067360016 = 10211035^2 + 5295004^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-132302303131241 is a prime.

It is a super-2 number, since 2×1323023031312412 (a number of 29 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (132302303131441) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66151151565620 + 66151151565621.

It is an arithmetic number, because the mean of its divisors is an integer number (66151151565621).

Almost surely, 2132302303131241 is an apocalyptic number.

It is an amenable number.

132302303131241 is a deficient number, since it is larger than the sum of its proper divisors (1).

132302303131241 is an equidigital number, since it uses as much as digits as its factorization.

132302303131241 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 7776, while the sum is 29.

Adding to 132302303131241 its reverse (142131303203231), we get a palindrome (274433606334472).

The spelling of 132302303131241 in words is "one hundred thirty-two trillion, three hundred two billion, three hundred three million, one hundred thirty-one thousand, two hundred forty-one".