Base | Representation |
---|---|
bin | 111101100110111010… |
… | …1010110000010110001 |
3 | 110122111101011211111101 |
4 | 1323031311112002301 |
5 | 4131423344111311 |
6 | 140440122044401 |
7 | 12362401160533 |
oct | 1731565260261 |
9 | 418441154441 |
10 | 132302332081 |
11 | 51122243317 |
12 | 21783949701 |
13 | c625b852ca |
14 | 6591183853 |
15 | 3695045ec1 |
hex | 1ecdd560b1 |
132302332081 has 2 divisors, whose sum is σ = 132302332082. Its totient is φ = 132302332080.
The previous prime is 132302332033. The next prime is 132302332111. The reversal of 132302332081 is 180233203231.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 125868848400 + 6433483681 = 354780^2 + 80209^2 .
It is a cyclic number.
It is not a de Polignac number, because 132302332081 - 211 = 132302330033 is a prime.
It is a super-2 number, since 2×1323023320812 (a number of 23 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (132302333081) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66151166040 + 66151166041.
It is an arithmetic number, because the mean of its divisors is an integer number (66151166041).
Almost surely, 2132302332081 is an apocalyptic number.
It is an amenable number.
132302332081 is a deficient number, since it is larger than the sum of its proper divisors (1).
132302332081 is an equidigital number, since it uses as much as digits as its factorization.
132302332081 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 5184, while the sum is 28.
The spelling of 132302332081 in words is "one hundred thirty-two billion, three hundred two million, three hundred thirty-two thousand, eighty-one".
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