Base | Representation |
---|---|
bin | 1100000010000110100010… |
… | …0111011000001111101011 |
3 | 1201211210121011211020201122 |
4 | 3000201220213120033223 |
5 | 3213231030113100232 |
6 | 44045521152005455 |
7 | 2533566016046321 |
oct | 300415047301753 |
9 | 51753534736648 |
10 | 13230254425067 |
11 | 4240a12790279 |
12 | 159814153088b |
13 | 74c7b8ca1254 |
14 | 33a4c225dd11 |
15 | 17e238c40312 |
hex | c08689d83eb |
13230254425067 has 2 divisors, whose sum is σ = 13230254425068. Its totient is φ = 13230254425066.
The previous prime is 13230254425021. The next prime is 13230254425121. The reversal of 13230254425067 is 76052445203231.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13230254425067 is a prime.
It is not a weakly prime, because it can be changed into another prime (13230254427067) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6615127212533 + 6615127212534.
It is an arithmetic number, because the mean of its divisors is an integer number (6615127212534).
Almost surely, 213230254425067 is an apocalyptic number.
13230254425067 is a deficient number, since it is larger than the sum of its proper divisors (1).
13230254425067 is an equidigital number, since it uses as much as digits as its factorization.
13230254425067 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1209600, while the sum is 44.
Adding to 13230254425067 its reverse (76052445203231), we get a palindrome (89282699628298).
The spelling of 13230254425067 in words is "thirteen trillion, two hundred thirty billion, two hundred fifty-four million, four hundred twenty-five thousand, sixty-seven".
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