Base | Representation |
---|---|
bin | 1100000010000110101101… |
… | …1101010111010000011111 |
3 | 1201211210201111120222021121 |
4 | 3000201223131113100133 |
5 | 3213231124321144411 |
6 | 44045530014311411 |
7 | 2533600135411333 |
oct | 300415335272037 |
9 | 51753644528247 |
10 | 13230302131231 |
11 | 4240a37704659 |
12 | 15981554b8567 |
13 | 74c7c5b35553 |
14 | 33a4c871b7c3 |
15 | 17e23d015571 |
hex | c086b75741f |
13230302131231 has 8 divisors (see below), whose sum is σ = 14008795416144. Its totient is φ = 12451835537280.
The previous prime is 13230302131217. The next prime is 13230302131313. The reversal of 13230302131231 is 13213120303231.
13230302131231 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 13230302131231 - 213 = 13230302123039 is a prime.
It is a super-2 number, since 2×132303021312312 (a number of 27 digits) contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 13230302131196 and 13230302131205.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13230302131031) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 5647705 + ... + 7639186.
It is an arithmetic number, because the mean of its divisors is an integer number (1751099427018).
Almost surely, 213230302131231 is an apocalyptic number.
13230302131231 is a deficient number, since it is larger than the sum of its proper divisors (778493284913).
13230302131231 is a wasteful number, since it uses less digits than its factorization.
13230302131231 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 13345481.
The product of its (nonzero) digits is 1944, while the sum is 25.
Adding to 13230302131231 its reverse (13213120303231), we get a palindrome (26443422434462).
The spelling of 13230302131231 in words is "thirteen trillion, two hundred thirty billion, three hundred two million, one hundred thirty-one thousand, two hundred thirty-one".
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