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132304443313140 = 223257337103562301
BaseRepresentation
bin11110000101010010000111…
…010110001000101111110100
3122100110011220010122212020100
4132011102013112020233310
5114320133444442010030
61145215453331434100
736603452304525000
oct3605220726105764
9570404803585210
10132304443313140
1139179aaa09822a
1212a095a2455930
1358a9342364a17
1424957d7d41700
15104681ed77360
hex785487588bf4

132304443313140 has 576 divisors, whose sum is σ = 485332302873600. Its totient is φ = 29137972147200.

The previous prime is 132304443313079. The next prime is 132304443313157. The reversal of 132304443313140 is 41313344403231.

132304443313140 is a `hidden beast` number, since 1 + 3 + 2 + 3 + 0 + 4 + 4 + 4 + 331 + 314 + 0 = 666.

It is a Harshad number since it is a multiple of its sum of digits (36).

It is a junction number, because it is equal to n+sod(n) for n = 132304443313095 and 132304443313104.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 191 ways as a sum of consecutive naturals, for example, 235009990 + ... + 235572290.

It is an arithmetic number, because the mean of its divisors is an integer number (842590803600).

Almost surely, 2132304443313140 is an apocalyptic number.

132304443313140 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 132304443313140, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (242666151436800).

132304443313140 is an abundant number, since it is smaller than the sum of its proper divisors (353027859560460).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

132304443313140 is a wasteful number, since it uses less digits than its factorization.

132304443313140 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 562477 (or 562458 counting only the distinct ones).

The product of its (nonzero) digits is 124416, while the sum is 36.

Adding to 132304443313140 its reverse (41313344403231), we get a palindrome (173617787716371).

The spelling of 132304443313140 in words is "one hundred thirty-two trillion, three hundred four billion, four hundred forty-three million, three hundred thirteen thousand, one hundred forty".