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132304444331111 = 1310177264948547
BaseRepresentation
bin11110000101010010000111…
…011010000001010001100111
3122100110011220012120120121222
4132011102013122001101213
5114320134000222043421
61145215453405330555
736603452316264563
oct3605220732012147
9570404805516558
10132304444331111
1139179aaa723028
1212a095a2866a5b
1358a9342630180
1424957d81286a3
15104681eec8cab
hex785487681467

132304444331111 has 4 divisors (see below), whose sum is σ = 142481709279672. Its totient is φ = 122127179382552.

The previous prime is 132304444331107. The next prime is 132304444331153. The reversal of 132304444331111 is 111133444403231.

It is a happy number.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 132304444331111 - 22 = 132304444331107 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (132304444337111) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5088632474261 + ... + 5088632474286.

It is an arithmetic number, because the mean of its divisors is an integer number (35620427319918).

Almost surely, 2132304444331111 is an apocalyptic number.

132304444331111 is a deficient number, since it is larger than the sum of its proper divisors (10177264948561).

132304444331111 is a wasteful number, since it uses less digits than its factorization.

132304444331111 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 10177264948560.

The product of its (nonzero) digits is 41472, while the sum is 35.

Adding to 132304444331111 its reverse (111133444403231), we get a palindrome (243437888734342).

The spelling of 132304444331111 in words is "one hundred thirty-two trillion, three hundred four billion, four hundred forty-four million, three hundred thirty-one thousand, one hundred eleven".

Divisors: 1 13 10177264948547 132304444331111