Base | Representation |
---|---|
bin | 11110000101010010000111… |
… | …011010000001010001100111 |
3 | 122100110011220012120120121222 |
4 | 132011102013122001101213 |
5 | 114320134000222043421 |
6 | 1145215453405330555 |
7 | 36603452316264563 |
oct | 3605220732012147 |
9 | 570404805516558 |
10 | 132304444331111 |
11 | 39179aaa723028 |
12 | 12a095a2866a5b |
13 | 58a9342630180 |
14 | 24957d81286a3 |
15 | 104681eec8cab |
hex | 785487681467 |
132304444331111 has 4 divisors (see below), whose sum is σ = 142481709279672. Its totient is φ = 122127179382552.
The previous prime is 132304444331107. The next prime is 132304444331153. The reversal of 132304444331111 is 111133444403231.
It is a happy number.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 132304444331111 - 22 = 132304444331107 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (132304444337111) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5088632474261 + ... + 5088632474286.
It is an arithmetic number, because the mean of its divisors is an integer number (35620427319918).
Almost surely, 2132304444331111 is an apocalyptic number.
132304444331111 is a deficient number, since it is larger than the sum of its proper divisors (10177264948561).
132304444331111 is a wasteful number, since it uses less digits than its factorization.
132304444331111 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 10177264948560.
The product of its (nonzero) digits is 41472, while the sum is 35.
Adding to 132304444331111 its reverse (111133444403231), we get a palindrome (243437888734342).
The spelling of 132304444331111 in words is "one hundred thirty-two trillion, three hundred four billion, four hundred forty-four million, three hundred thirty-one thousand, one hundred eleven".
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