Base | Representation |
---|---|
bin | 1100000010001001011011… |
… | …1010100111011111101011 |
3 | 1201211212121022111112022212 |
4 | 3000202112322213133223 |
5 | 3213234122443021303 |
6 | 44050130221235335 |
7 | 2533624200515216 |
oct | 300422672473753 |
9 | 51755538445285 |
10 | 13231031220203 |
11 | 4241281211a25 |
12 | 1598319702b4b |
13 | 74c8b0bbb044 |
14 | 33a5574a877d |
15 | 17e282031ad8 |
hex | c0896ea77eb |
13231031220203 has 2 divisors, whose sum is σ = 13231031220204. Its totient is φ = 13231031220202.
The previous prime is 13231031220163. The next prime is 13231031220217. The reversal of 13231031220203 is 30202213013231.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13231031220203 - 232 = 13226736252907 is a prime.
It is a super-2 number, since 2×132310312202032 (a number of 27 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (13231031220223) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6615515610101 + 6615515610102.
It is an arithmetic number, because the mean of its divisors is an integer number (6615515610102).
Almost surely, 213231031220203 is an apocalyptic number.
13231031220203 is a deficient number, since it is larger than the sum of its proper divisors (1).
13231031220203 is an equidigital number, since it uses as much as digits as its factorization.
13231031220203 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1296, while the sum is 23.
Adding to 13231031220203 its reverse (30202213013231), we get a palindrome (43433244233434).
The spelling of 13231031220203 in words is "thirteen trillion, two hundred thirty-one billion, thirty-one million, two hundred twenty thousand, two hundred three".
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