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1323111031211 is a prime number
BaseRepresentation
bin10011010000001111100…
…100000010000110101011
311200111011212211111000002
4103100033210002012223
5133134212410444321
62451455005133215
7164406632126204
oct23201744020653
94614155744002
101323111031211
11470145757a92
1219451725a20b
13979cc190138
1448078ada5ab
152463cd6820b
hex1340f9021ab

1323111031211 has 2 divisors, whose sum is σ = 1323111031212. Its totient is φ = 1323111031210.

The previous prime is 1323111031171. The next prime is 1323111031267. The reversal of 1323111031211 is 1121301113231.

It is a weak prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1323111031211 is a prime.

It is a super-2 number, since 2×13231110312112 (a number of 25 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (1323111031111) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 661555515605 + 661555515606.

It is an arithmetic number, because the mean of its divisors is an integer number (661555515606).

Almost surely, 21323111031211 is an apocalyptic number.

1323111031211 is a deficient number, since it is larger than the sum of its proper divisors (1).

1323111031211 is an equidigital number, since it uses as much as digits as its factorization.

1323111031211 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 108, while the sum is 20.

Adding to 1323111031211 its reverse (1121301113231), we get a palindrome (2444412144442).

The spelling of 1323111031211 in words is "one trillion, three hundred twenty-three billion, one hundred eleven million, thirty-one thousand, two hundred eleven".