Base | Representation |
---|---|
bin | 11000101001010001… |
… | …01100001110100010 |
3 | 1021011002200012001202 |
4 | 30110220230032202 |
5 | 204044131104442 |
6 | 10024524401202 |
7 | 645610414553 |
oct | 142450541642 |
9 | 37132605052 |
10 | 13231113122 |
11 | 567a689137 |
12 | 26930a6202 |
13 | 132b230826 |
14 | 8d732a32a |
15 | 5268a4c32 |
hex | 314a2c3a2 |
13231113122 has 4 divisors (see below), whose sum is σ = 19846669686. Its totient is φ = 6615556560.
The previous prime is 13231113113. The next prime is 13231113139. The reversal of 13231113122 is 22131113231.
It is a happy number.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 22131113231 = 103 ⋅214865177.
It can be written as a sum of positive squares in only one way, i.e., 7710771721 + 5520341401 = 87811^2 + 74299^2 .
It is a super-4 number, since 4×132311131224 (a number of 42 digits) contains 4444 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 13231113094 and 13231113103.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3307778279 + ... + 3307778282.
Almost surely, 213231113122 is an apocalyptic number.
13231113122 is a deficient number, since it is larger than the sum of its proper divisors (6615556564).
13231113122 is an equidigital number, since it uses as much as digits as its factorization.
13231113122 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 6615556563.
The product of its digits is 216, while the sum is 20.
Adding to 13231113122 its reverse (22131113231), we get a palindrome (35362226353).
The spelling of 13231113122 in words is "thirteen billion, two hundred thirty-one million, one hundred thirteen thousand, one hundred twenty-two".
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