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132311320043 = 747402162067
BaseRepresentation
bin111101100111001011…
…1101000010111101011
3110122112000002110122212
41323032113220113223
54131433144220133
6140441042435335
712362540443520
oct1731627502753
9418460073585
10132311320043
1151127322091
1221786962b4b
13c6279b1326
146592443147
153695c1e148
hex1ece5e85eb

132311320043 has 8 divisors (see below), whose sum is σ = 154430234112. Its totient is φ = 110996730216.

The previous prime is 132311320039. The next prime is 132311320067. The reversal of 132311320043 is 340023113231.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 132311320043 - 22 = 132311320039 is a prime.

It is not an unprimeable number, because it can be changed into a prime (132311320343) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 201080705 + ... + 201081362.

It is an arithmetic number, because the mean of its divisors is an integer number (19303779264).

Almost surely, 2132311320043 is an apocalyptic number.

132311320043 is a deficient number, since it is larger than the sum of its proper divisors (22118914069).

132311320043 is an equidigital number, since it uses as much as digits as its factorization.

132311320043 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 402162121.

The product of its (nonzero) digits is 1296, while the sum is 23.

Adding to 132311320043 its reverse (340023113231), we get a palindrome (472334433274).

The spelling of 132311320043 in words is "one hundred thirty-two billion, three hundred eleven million, three hundred twenty thousand, forty-three".

Divisors: 1 7 47 329 402162067 2815134469 18901617149 132311320043