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132312112441 = 269491866589
BaseRepresentation
bin111101100111001101…
…0101001110100111001
3110122112001120201121221
41323032122221310321
54131433400044231
6140441111432041
712362550253645
oct1731632516471
9418461521557
10132312112441
1151127813463
1221787085621
13c627bcabc2
1465925abc25
153695d28d11
hex1ece6a9d39

132312112441 has 4 divisors (see below), whose sum is σ = 132803979300. Its totient is φ = 131820245584.

The previous prime is 132312112421. The next prime is 132312112469. The reversal of 132312112441 is 144211213231.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 144211213231 = 178483012543.

It can be written as a sum of positive squares in 2 ways, for example, as 4574493225 + 127737619216 = 67635^2 + 357404^2 .

It is a cyclic number.

It is not a de Polignac number, because 132312112441 - 27 = 132312112313 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (132312112421) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 245933026 + ... + 245933563.

It is an arithmetic number, because the mean of its divisors is an integer number (33200994825).

Almost surely, 2132312112441 is an apocalyptic number.

It is an amenable number.

132312112441 is a deficient number, since it is larger than the sum of its proper divisors (491866859).

132312112441 is an equidigital number, since it uses as much as digits as its factorization.

132312112441 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 491866858.

The product of its digits is 1152, while the sum is 25.

Adding to 132312112441 its reverse (144211213231), we get a palindrome (276523325672).

The spelling of 132312112441 in words is "one hundred thirty-two billion, three hundred twelve million, one hundred twelve thousand, four hundred forty-one".

Divisors: 1 269 491866589 132312112441