Base | Representation |
---|---|
bin | 11110000101011001010000… |
… | …111011111010010001101011 |
3 | 122100110220201011110102202201 |
4 | 132011121100323322101223 |
5 | 114320300210310344201 |
6 | 1145223203214241031 |
7 | 36604143454646221 |
oct | 3605312073722153 |
9 | 570426634412681 |
10 | 132312120403051 |
11 | 39182289663536 |
12 | 12a0ab854b6177 |
13 | 58a9c96a18184 |
14 | 2495d25790b11 |
15 | 1046b1dd3a801 |
hex | 785650efa46b |
132312120403051 has 2 divisors, whose sum is σ = 132312120403052. Its totient is φ = 132312120403050.
The previous prime is 132312120403013. The next prime is 132312120403123. The reversal of 132312120403051 is 150304021213231.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-132312120403051 is a prime.
It is not a weakly prime, because it can be changed into another prime (132312120403951) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66156060201525 + 66156060201526.
It is an arithmetic number, because the mean of its divisors is an integer number (66156060201526).
Almost surely, 2132312120403051 is an apocalyptic number.
132312120403051 is a deficient number, since it is larger than the sum of its proper divisors (1).
132312120403051 is an equidigital number, since it uses as much as digits as its factorization.
132312120403051 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 4320, while the sum is 28.
Adding to 132312120403051 its reverse (150304021213231), we get a palindrome (282616141616282).
The spelling of 132312120403051 in words is "one hundred thirty-two trillion, three hundred twelve billion, one hundred twenty million, four hundred three thousand, fifty-one".
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