Base | Representation |
---|---|
bin | 10011010000010000110… |
… | …011101111000000010001 |
3 | 11200111020100010222012111 |
4 | 103100100303233000101 |
5 | 133134233233040442 |
6 | 2451501033025321 |
7 | 164410304535445 |
oct | 23202063570021 |
9 | 4614210128174 |
10 | 1323131924497 |
11 | 470156528469 |
12 | 194522255241 |
13 | 97a035c7026 |
14 | 4807b7b8825 |
15 | 2463eae3b17 |
hex | 13410cef011 |
1323131924497 has 2 divisors, whose sum is σ = 1323131924498. Its totient is φ = 1323131924496.
The previous prime is 1323131924489. The next prime is 1323131924501. The reversal of 1323131924497 is 7944291313231.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1320915774721 + 2216149776 = 1149311^2 + 47076^2 .
It is a cyclic number.
It is not a de Polignac number, because 1323131924497 - 23 = 1323131924489 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 1323131924497.
It is not a weakly prime, because it can be changed into another prime (1323131925497) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 661565962248 + 661565962249.
It is an arithmetic number, because the mean of its divisors is an integer number (661565962249).
Almost surely, 21323131924497 is an apocalyptic number.
It is an amenable number.
1323131924497 is a deficient number, since it is larger than the sum of its proper divisors (1).
1323131924497 is an equidigital number, since it uses as much as digits as its factorization.
1323131924497 is an evil number, because the sum of its binary digits is even.
The product of its digits is 979776, while the sum is 49.
The spelling of 1323131924497 in words is "one trillion, three hundred twenty-three billion, one hundred thirty-one million, nine hundred twenty-four thousand, four hundred ninety-seven".
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