Base | Representation |
---|---|
bin | 1100000010001010100000… |
… | …1100110100001000011111 |
3 | 1201211220100112011012021000 |
4 | 3000202220030310020133 |
5 | 3213240221212000411 |
6 | 44050215100441343 |
7 | 2533634321364615 |
oct | 300425014641037 |
9 | 51756315135230 |
10 | 13231321203231 |
11 | 424140a97451a |
12 | 159839a849253 |
13 | 74c928cbc631 |
14 | 33a583bd16b5 |
15 | 17e29c712956 |
hex | c08a833421f |
13231321203231 has 48 divisors (see below), whose sum is σ = 20476325160480. Its totient is φ = 8441780808960.
The previous prime is 13231321203209. The next prime is 13231321203263. The reversal of 13231321203231 is 13230212313231.
13231321203231 is a `hidden beast` number, since 1 + 3 + 2 + 313 + 2 + 1 + 20 + 323 + 1 = 666.
It is not a de Polignac number, because 13231321203231 - 29 = 13231321202719 is a prime.
It is a super-2 number, since 2×132313212032312 (a number of 27 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (27).
It is a junction number, because it is equal to n+sod(n) for n = 13231321203195 and 13231321203204.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13231321203631) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 679366 + ... + 5188851.
It is an arithmetic number, because the mean of its divisors is an integer number (426590107510).
Almost surely, 213231321203231 is an apocalyptic number.
13231321203231 is a deficient number, since it is larger than the sum of its proper divisors (7245003957249).
13231321203231 is an equidigital number, since it uses as much as digits as its factorization.
13231321203231 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 5868361 (or 5868318 counting only the distinct ones).
The product of its (nonzero) digits is 3888, while the sum is 27.
Adding to 13231321203231 its reverse (13230212313231), we get a palindrome (26461533516462).
Subtracting from 13231321203231 its reverse (13230212313231), we obtain a square (1108890000 = 333002).
The spelling of 13231321203231 in words is "thirteen trillion, two hundred thirty-one billion, three hundred twenty-one million, two hundred three thousand, two hundred thirty-one".
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