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13231450415400 = 2335275179760821
BaseRepresentation
bin1100000010001010111111…
…1001101110000100101000
31201211220200112021212000220
43000202233321232010220
53213241002301243100
644050235554130040
72533640450564520
oct300425771560450
951756615255026
1013231450415400
1142414768a8538
121598415b80920
1374c9499c0639
1433a597028680
1517e2a8c37aa0
hexc08afe6e128

13231450415400 has 192 divisors, whose sum is σ = 46878814385280. Its totient is φ = 3024223411200.

The previous prime is 13231450415363. The next prime is 13231450415419. The reversal of 13231450415400 is 451405413231.

It is an unprimeable number.

It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 217516990 + ... + 217577810.

It is an arithmetic number, because the mean of its divisors is an integer number (244160491590).

Almost surely, 213231450415400 is an apocalyptic number.

13231450415400 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

13231450415400 is an abundant number, since it is smaller than the sum of its proper divisors (33647363969880).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13231450415400 is a wasteful number, since it uses less digits than its factorization.

13231450415400 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 112644 (or 112635 counting only the distinct ones).

The product of its (nonzero) digits is 28800, while the sum is 33.

Adding to 13231450415400 its reverse (451405413231), we get a palindrome (13682855828631).

The spelling of 13231450415400 in words is "thirteen trillion, two hundred thirty-one billion, four hundred fifty million, four hundred fifteen thousand, four hundred".