Base | Representation |
---|---|
bin | 11110000101011100001010… |
… | …010101110001110101011001 |
3 | 122100111012201221112120022112 |
4 | 132011130022111301311121 |
5 | 114320323043112003202 |
6 | 1145224440012402105 |
7 | 36604313525222144 |
oct | 3605341225616531 |
9 | 570435657476275 |
10 | 132315230969177 |
11 | 39183635481943 |
12 | 12a0b6b3176335 |
13 | 58aa3712a2649 |
14 | 249613c93905b |
15 | 1046c51e6eb52 |
hex | 78570a571d59 |
132315230969177 has 2 divisors, whose sum is σ = 132315230969178. Its totient is φ = 132315230969176.
The previous prime is 132315230969149. The next prime is 132315230969189. The reversal of 132315230969177 is 771969032513231.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 113248524465241 + 19066706503936 = 10641829^2 + 4366544^2 .
It is a cyclic number.
It is not a de Polignac number, because 132315230969177 - 222 = 132315226774873 is a prime.
It is not a weakly prime, because it can be changed into another prime (132315230969107) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66157615484588 + 66157615484589.
It is an arithmetic number, because the mean of its divisors is an integer number (66157615484589).
Almost surely, 2132315230969177 is an apocalyptic number.
It is an amenable number.
132315230969177 is a deficient number, since it is larger than the sum of its proper divisors (1).
132315230969177 is an equidigital number, since it uses as much as digits as its factorization.
132315230969177 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 12859560, while the sum is 59.
The spelling of 132315230969177 in words is "one hundred thirty-two trillion, three hundred fifteen billion, two hundred thirty million, nine hundred sixty-nine thousand, one hundred seventy-seven".
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