Base | Representation |
---|---|
bin | 11110000101100001101000… |
… | …110100110111010000001010 |
3 | 122100111202220202010100222021 |
4 | 132011201220310313100022 |
5 | 114320422113423042214 |
6 | 1145231251305115054 |
7 | 36604612325663263 |
oct | 3605415064672012 |
9 | 570452822110867 |
10 | 132321111143434 |
11 | 391860826aa894 |
12 | 12a10874488a8a |
13 | 58aaa9a5a58b5 |
14 | 249653987596a |
15 | 1046e982d8924 |
hex | 785868d3740a |
132321111143434 has 4 divisors (see below), whose sum is σ = 198481666715154. Its totient is φ = 66160555571716.
The previous prime is 132321111143423. The next prime is 132321111143443. The reversal of 132321111143434 is 434341111123231.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 72915323668209 + 59405787475225 = 8539047^2 + 7707515^2 .
It is a self number, because there is not a number n which added to its sum of digits gives 132321111143434.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 33080277785857 + ... + 33080277785860.
Almost surely, 2132321111143434 is an apocalyptic number.
132321111143434 is a deficient number, since it is larger than the sum of its proper divisors (66160555571720).
132321111143434 is an equidigital number, since it uses as much as digits as its factorization.
132321111143434 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 66160555571719.
The product of its digits is 20736, while the sum is 34.
Adding to 132321111143434 its reverse (434341111123231), we get a palindrome (566662222266665).
The spelling of 132321111143434 in words is "one hundred thirty-two trillion, three hundred twenty-one billion, one hundred eleven million, one hundred forty-three thousand, four hundred thirty-four".
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