Base | Representation |
---|---|
bin | 11110000101100001101000… |
… | …111101011110001111101101 |
3 | 122100111202220220101000210221 |
4 | 132011201220331132033231 |
5 | 114320422120012302201 |
6 | 1145231251425331341 |
7 | 36604612354113130 |
oct | 3605415075361755 |
9 | 570452826330727 |
10 | 132321113400301 |
11 | 39186083a01471 |
12 | 12a10875196b51 |
13 | 58aaa9abb5c17 |
14 | 2496539ca2217 |
15 | 1046e985d24a1 |
hex | 785868f5e3ed |
132321113400301 has 8 divisors (see below), whose sum is σ = 151225423856640. Its totient is φ = 113417126508048.
The previous prime is 132321113400253. The next prime is 132321113400319. The reversal of 132321113400301 is 103004311123231.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 132321113400301 - 217 = 132321113269229 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (132321113400901) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 80014066 + ... + 81651043.
It is an arithmetic number, because the mean of its divisors is an integer number (18903177982080).
Almost surely, 2132321113400301 is an apocalyptic number.
It is an amenable number.
132321113400301 is a deficient number, since it is larger than the sum of its proper divisors (18904310456339).
132321113400301 is a wasteful number, since it uses less digits than its factorization.
132321113400301 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 161782043.
The product of its (nonzero) digits is 1296, while the sum is 25.
Adding to 132321113400301 its reverse (103004311123231), we get a palindrome (235325424523532).
The spelling of 132321113400301 in words is "one hundred thirty-two trillion, three hundred twenty-one billion, one hundred thirteen million, four hundred thousand, three hundred one".
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