Base | Representation |
---|---|
bin | 11110000101100001101110… |
… | …111010110000010010110011 |
3 | 122100111210011212110001112001 |
4 | 132011201232322300102303 |
5 | 114320422321104213331 |
6 | 1145231305355514431 |
7 | 36604615006511632 |
oct | 3605415672602263 |
9 | 570453155401461 |
10 | 132321213351091 |
11 | 39186125369a26 |
12 | 12a108a2758a17 |
13 | 58aaab58101bb |
14 | 249654927d519 |
15 | 1046ea2277561 |
hex | 78586eeb04b3 |
132321213351091 has 2 divisors, whose sum is σ = 132321213351092. Its totient is φ = 132321213351090.
The previous prime is 132321213351007. The next prime is 132321213351097. The reversal of 132321213351091 is 190153312123231.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 132321213351091 - 221 = 132321211253939 is a prime.
It is a super-2 number, since 2×1323212133510912 (a number of 29 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 132321213351091.
It is not a weakly prime, because it can be changed into another prime (132321213351097) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66160606675545 + 66160606675546.
It is an arithmetic number, because the mean of its divisors is an integer number (66160606675546).
Almost surely, 2132321213351091 is an apocalyptic number.
132321213351091 is a deficient number, since it is larger than the sum of its proper divisors (1).
132321213351091 is an equidigital number, since it uses as much as digits as its factorization.
132321213351091 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 29160, while the sum is 37.
The spelling of 132321213351091 in words is "one hundred thirty-two trillion, three hundred twenty-one billion, two hundred thirteen million, three hundred fifty-one thousand, ninety-one".
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