Base | Representation |
---|---|
bin | 11110000101100010000011… |
… | …101101100110010111000011 |
3 | 122100111211002011220122021101 |
4 | 132011202003231212113003 |
5 | 114320424024412132232 |
6 | 1145231404141235231 |
7 | 36604626444053206 |
oct | 3605420355462703 |
9 | 570454064818241 |
10 | 132321562224067 |
11 | 391862942943a7 |
12 | 12a1097b562b17 |
13 | 58aab3cb90408 |
14 | 249657d73593d |
15 | 1046ec2bdc1e7 |
hex | 785883b665c3 |
132321562224067 has 2 divisors, whose sum is σ = 132321562224068. Its totient is φ = 132321562224066.
The previous prime is 132321562224041. The next prime is 132321562224073. The reversal of 132321562224067 is 760422265123231.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-132321562224067 is a prime.
It is not a weakly prime, because it can be changed into another prime (132321562234067) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66160781112033 + 66160781112034.
It is an arithmetic number, because the mean of its divisors is an integer number (66160781112034).
Almost surely, 2132321562224067 is an apocalyptic number.
132321562224067 is a deficient number, since it is larger than the sum of its proper divisors (1).
132321562224067 is an equidigital number, since it uses as much as digits as its factorization.
132321562224067 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1451520, while the sum is 46.
The spelling of 132321562224067 in words is "one hundred thirty-two trillion, three hundred twenty-one billion, five hundred sixty-two million, two hundred twenty-four thousand, sixty-seven".
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