Base | Representation |
---|---|
bin | 10011010000010110001… |
… | …111111011011000110011 |
3 | 11200111110200220022110222 |
4 | 103100112033323120303 |
5 | 133134430114420311 |
6 | 2451514053243255 |
7 | 164412463426613 |
oct | 23202617733063 |
9 | 4614420808428 |
10 | 1323223201331 |
11 | 4701a3001069 |
12 | 19454893352b |
13 | 97a194a51a5 |
14 | 48089978a43 |
15 | 24647b23adb |
hex | 134163fb633 |
1323223201331 has 2 divisors, whose sum is σ = 1323223201332. Its totient is φ = 1323223201330.
The previous prime is 1323223201303. The next prime is 1323223201343. The reversal of 1323223201331 is 1331023223231.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1323223201331 - 210 = 1323223200307 is a prime.
It is a super-2 number, since 2×13232232013312 (a number of 25 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 1323223201331.
It is not a weakly prime, because it can be changed into another prime (1323223201301) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 661611600665 + 661611600666.
It is an arithmetic number, because the mean of its divisors is an integer number (661611600666).
Almost surely, 21323223201331 is an apocalyptic number.
1323223201331 is a deficient number, since it is larger than the sum of its proper divisors (1).
1323223201331 is an equidigital number, since it uses as much as digits as its factorization.
1323223201331 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 3888, while the sum is 26.
Adding to 1323223201331 its reverse (1331023223231), we get a palindrome (2654246424562).
The spelling of 1323223201331 in words is "one trillion, three hundred twenty-three billion, two hundred twenty-three million, two hundred one thousand, three hundred thirty-one".
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