13232234031 has 4 divisors (see below), whose sum is σ = 17642978712. Its totient is φ = 8821489352.

The previous prime is 13232234021. The next prime is 13232234047. The reversal of 13232234031 is 13043223231.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 13043223231 = 3 ⋅4347741077.

It is a cyclic number.

It is not a de Polignac number, because 13232234031 - 2¹⁷ = 13232102959 is a prime.

It is a super-2 number, since 2×13232234031² (a number of 21 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 13232233992 and 13232234010.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13232234021) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2205372336 + ... + 2205372341.

It is an arithmetic number, because the mean of its divisors is an integer number (4410744678).

Almost surely, 2^13232234031 is an apocalyptic number.

13232234031 is a deficient number, since it is larger than the sum of its proper divisors (4410744681).

13232234031 is an equidigital number, since it uses as much as digits as its factorization.

13232234031 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4410744680.

The product of its (nonzero) digits is 2592, while the sum is 24.

Adding to 13232234031 its reverse (13043223231), we get a palindrome (26275457262).

The spelling of 13232234031 in words is "thirteen billion, two hundred thirty-two million, two hundred thirty-four thousand, thirty-one".