Base | Representation |
---|---|
bin | 11000101001011010… |
… | …10011001000111011 |
3 | 1021011011221120002001 |
4 | 30110231103020323 |
5 | 204044433233313 |
6 | 10025010321431 |
7 | 645623605402 |
oct | 142455231073 |
9 | 37134846061 |
10 | 13232321083 |
11 | 5680333753 |
12 | 2693589277 |
13 | 132b5645b7 |
14 | 8d7562639 |
15 | 526a42add |
hex | 314b5323b |
13232321083 has 2 divisors, whose sum is σ = 13232321084. Its totient is φ = 13232321082.
The previous prime is 13232321051. The next prime is 13232321143. The reversal of 13232321083 is 38012323231.
13232321083 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 13232321083 - 25 = 13232321051 is a prime.
It is not a weakly prime, because it can be changed into another prime (13232321033) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6616160541 + 6616160542.
It is an arithmetic number, because the mean of its divisors is an integer number (6616160542).
Almost surely, 213232321083 is an apocalyptic number.
13232321083 is a deficient number, since it is larger than the sum of its proper divisors (1).
13232321083 is an equidigital number, since it uses as much as digits as its factorization.
13232321083 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 5184, while the sum is 28.
The spelling of 13232321083 in words is "thirteen billion, two hundred thirty-two million, three hundred twenty-one thousand, eighty-three".
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