Base | Representation |
---|---|
bin | 1100000010001110010010… |
… | …0100110111001011100011 |
3 | 1201211222222010011201110111 |
4 | 3000203210210313023203 |
5 | 3213244310014441011 |
6 | 44050503403312151 |
7 | 2534001401246461 |
oct | 300434444671343 |
9 | 51758863151414 |
10 | 13232334140131 |
11 | 424188a723a57 |
12 | 1598621b1b657 |
13 | 74ca5ab09092 |
14 | 33a63c549831 |
15 | 17e30b5ec121 |
hex | c08e49372e3 |
13232334140131 has 2 divisors, whose sum is σ = 13232334140132. Its totient is φ = 13232334140130.
The previous prime is 13232334140099. The next prime is 13232334140153. The reversal of 13232334140131 is 13104143323231.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13232334140131 - 25 = 13232334140099 is a prime.
It is a super-2 number, since 2×132323341401312 (a number of 27 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 13232334140093 and 13232334140102.
It is not a weakly prime, because it can be changed into another prime (13232334140161) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6616167070065 + 6616167070066.
It is an arithmetic number, because the mean of its divisors is an integer number (6616167070066).
Almost surely, 213232334140131 is an apocalyptic number.
13232334140131 is a deficient number, since it is larger than the sum of its proper divisors (1).
13232334140131 is an equidigital number, since it uses as much as digits as its factorization.
13232334140131 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 15552, while the sum is 31.
Adding to 13232334140131 its reverse (13104143323231), we get a palindrome (26336477463362).
The spelling of 13232334140131 in words is "thirteen trillion, two hundred thirty-two billion, three hundred thirty-four million, one hundred forty thousand, one hundred thirty-one".
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