Base | Representation |
---|---|
bin | 11000101001011011… |
… | …01001001000001011 |
3 | 1021011012010010121202 |
4 | 30110231221020023 |
5 | 204044444124042 |
6 | 10025012254415 |
7 | 645624432104 |
oct | 142455511013 |
9 | 37135103552 |
10 | 13232411147 |
11 | 568039538a |
12 | 269361140b |
13 | 132b5965a7 |
14 | 8d75873ab |
15 | 526a5e632 |
hex | 314b6920b |
13232411147 has 2 divisors, whose sum is σ = 13232411148. Its totient is φ = 13232411146.
The previous prime is 13232411119. The next prime is 13232411177. The reversal of 13232411147 is 74111423231.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 13232411147 - 216 = 13232345611 is a prime.
It is not a weakly prime, because it can be changed into another prime (13232411177) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6616205573 + 6616205574.
It is an arithmetic number, because the mean of its divisors is an integer number (6616205574).
Almost surely, 213232411147 is an apocalyptic number.
13232411147 is a deficient number, since it is larger than the sum of its proper divisors (1).
13232411147 is an equidigital number, since it uses as much as digits as its factorization.
13232411147 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 4032, while the sum is 29.
Adding to 13232411147 its reverse (74111423231), we get a palindrome (87343834378).
The spelling of 13232411147 in words is "thirteen billion, two hundred thirty-two million, four hundred eleven thousand, one hundred forty-seven".
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