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1323254400143 = 13773131680207
BaseRepresentation
bin10011010000011000000…
…110111100010010001111
311200111112212121101012112
4103100120012330102033
5133140011111301033
62451521130054235
7164413322550344
oct23203006742217
94614485541175
101323254400143
11470209680205
1219455727a37b
1397a22aa9a20
144808db7a7cb
152464a737c48
hex134181bc48f

1323254400143 has 8 divisors (see below), whose sum is σ = 1426886733888. Its totient is φ = 1219885428384.

The previous prime is 1323254400119. The next prime is 1323254400157. The reversal of 1323254400143 is 3410044523231.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1323254400143 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1323254400043) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 65830055 + ... + 65850152.

It is an arithmetic number, because the mean of its divisors is an integer number (178360841736).

Almost surely, 21323254400143 is an apocalyptic number.

1323254400143 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

1323254400143 is a deficient number, since it is larger than the sum of its proper divisors (103632333745).

1323254400143 is a wasteful number, since it uses less digits than its factorization.

1323254400143 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 131680993.

The product of its (nonzero) digits is 34560, while the sum is 32.

Adding to 1323254400143 its reverse (3410044523231), we get a palindrome (4733298923374).

The spelling of 1323254400143 in words is "one trillion, three hundred twenty-three billion, two hundred fifty-four million, four hundred thousand, one hundred forty-three".

Divisors: 1 13 773 10049 131680207 1711842691 101788800011 1323254400143