Base | Representation |
---|---|
bin | 111101100111101111… |
… | …1010100100001101011 |
3 | 110122120022110020221011 |
4 | 1323033133110201223 |
5 | 4132003002110011 |
6 | 140442553324351 |
7 | 12363156255046 |
oct | 1731737244153 |
9 | 418508406834 |
10 | 132330113131 |
11 | 51136998667 |
12 | 217911066b7 |
13 | c62b8612b8 |
14 | 6594b35c5d |
15 | 36976d2621 |
hex | 1ecf7d486b |
132330113131 has 2 divisors, whose sum is σ = 132330113132. Its totient is φ = 132330113130.
The previous prime is 132330113101. The next prime is 132330113147. The reversal of 132330113131 is 131311033231.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 132330113131 - 25 = 132330113099 is a prime.
It is a super-2 number, since 2×1323301131312 (a number of 23 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (132330113101) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66165056565 + 66165056566.
It is an arithmetic number, because the mean of its divisors is an integer number (66165056566).
Almost surely, 2132330113131 is an apocalyptic number.
132330113131 is a deficient number, since it is larger than the sum of its proper divisors (1).
132330113131 is an equidigital number, since it uses as much as digits as its factorization.
132330113131 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 486, while the sum is 22.
Adding to 132330113131 its reverse (131311033231), we get a palindrome (263641146362).
The spelling of 132330113131 in words is "one hundred thirty-two billion, three hundred thirty million, one hundred thirteen thousand, one hundred thirty-one".
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