Base | Representation |
---|---|
bin | 10011010000011011100… |
… | …111101101010011010011 |
3 | 11200111200222110212122211 |
4 | 103100123213231103103 |
5 | 133140121202234141 |
6 | 2451531033012551 |
7 | 164414636431642 |
oct | 23203347552323 |
9 | 4614628425584 |
10 | 1323313321171 |
11 | 470239964476 |
12 | 194572b54157 |
13 | 97a3206983a |
14 | 48097917359 |
15 | 246509c5d81 |
hex | 1341b9ed4d3 |
1323313321171 has 2 divisors, whose sum is σ = 1323313321172. Its totient is φ = 1323313321170.
The previous prime is 1323313321151. The next prime is 1323313321223. The reversal of 1323313321171 is 1711233133231.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1323313321171 - 215 = 1323313288403 is a prime.
It is a super-2 number, since 2×13233133211712 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1323313321151) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 661656660585 + 661656660586.
It is an arithmetic number, because the mean of its divisors is an integer number (661656660586).
Almost surely, 21323313321171 is an apocalyptic number.
1323313321171 is a deficient number, since it is larger than the sum of its proper divisors (1).
1323313321171 is an equidigital number, since it uses as much as digits as its factorization.
1323313321171 is an evil number, because the sum of its binary digits is even.
The product of its digits is 6804, while the sum is 31.
The spelling of 1323313321171 in words is "one trillion, three hundred twenty-three billion, three hundred thirteen million, three hundred twenty-one thousand, one hundred seventy-one".
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