Base | Representation |
---|---|
bin | 11110000101101011001111… |
… | …011010110110101000101001 |
3 | 122100112202112100102001111102 |
4 | 132011223033122312220221 |
5 | 114321104223103004001 |
6 | 1145240114405211145 |
7 | 36605426002325162 |
oct | 3605531732665051 |
9 | 570482470361442 |
10 | 132331422313001 |
11 | 3918a49402812a |
12 | 12a12871700ab5 |
13 | 58aba518a1b72 |
14 | 2496c37078769 |
15 | 104739d65ee6b |
hex | 785acf6b6a29 |
132331422313001 has 2 divisors, whose sum is σ = 132331422313002. Its totient is φ = 132331422313000.
The previous prime is 132331422312997. The next prime is 132331422313043. The reversal of 132331422313001 is 100313224133231.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 73073449986601 + 59257972326400 = 8548301^2 + 7697920^2 .
It is a cyclic number.
It is not a de Polignac number, because 132331422313001 - 22 = 132331422312997 is a prime.
It is not a weakly prime, because it can be changed into another prime (132331422313081) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66165711156500 + 66165711156501.
It is an arithmetic number, because the mean of its divisors is an integer number (66165711156501).
Almost surely, 2132331422313001 is an apocalyptic number.
It is an amenable number.
132331422313001 is a deficient number, since it is larger than the sum of its proper divisors (1).
132331422313001 is an equidigital number, since it uses as much as digits as its factorization.
132331422313001 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 7776, while the sum is 29.
Adding to 132331422313001 its reverse (100313224133231), we get a palindrome (232644646446232).
The spelling of 132331422313001 in words is "one hundred thirty-two trillion, three hundred thirty-one billion, four hundred twenty-two million, three hundred thirteen thousand, one".
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