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132334305113551 = 196964963427029
BaseRepresentation
bin11110000101101101111011…
…001111110111010111001111
3122100120000222020220111102011
4132011231323033313113033
5114321131124102113201
61145241312425442051
736605560305612412
oct3605557317672717
9570500866814364
10132334305113551
1139190733319922
1212a13337040327
1358ac0c0c000c8
14249702bc93b79
1510474bb7a3151
hex785b7b3f75cf

132334305113551 has 4 divisors (see below), whose sum is σ = 139299268540600. Its totient is φ = 125369341686504.

The previous prime is 132334305113509. The next prime is 132334305113579. The reversal of 132334305113551 is 155311503433231.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 132334305113551 - 229 = 132333768242639 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (132334305110551) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3482481713496 + ... + 3482481713533.

It is an arithmetic number, because the mean of its divisors is an integer number (34824817135150).

Almost surely, 2132334305113551 is an apocalyptic number.

132334305113551 is a deficient number, since it is larger than the sum of its proper divisors (6964963427049).

132334305113551 is an equidigital number, since it uses as much as digits as its factorization.

132334305113551 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 6964963427048.

The product of its (nonzero) digits is 243000, while the sum is 40.

Adding to 132334305113551 its reverse (155311503433231), we get a palindrome (287645808546782).

The spelling of 132334305113551 in words is "one hundred thirty-two trillion, three hundred thirty-four billion, three hundred five million, one hundred thirteen thousand, five hundred fifty-one".

Divisors: 1 19 6964963427029 132334305113551