Base | Representation |
---|---|
bin | 11110000101101101111011… |
… | …001111110111010111010000 |
3 | 122100120000222020220111102012 |
4 | 132011231323033313113100 |
5 | 114321131124102113202 |
6 | 1145241312425442052 |
7 | 36605560305612413 |
oct | 3605557317672720 |
9 | 570500866814365 |
10 | 132334305113552 |
11 | 39190733319923 |
12 | 12a13337040328 |
13 | 58ac0c0c000c9 |
14 | 249702bc93b7a |
15 | 10474bb7a3152 |
hex | 785b7b3f75d0 |
132334305113552 has 10 divisors (see below), whose sum is σ = 256397716157538. Its totient is φ = 66167152556768.
The previous prime is 132334305113509. The next prime is 132334305113579. The reversal of 132334305113552 is 255311503433231.
It can be written as a sum of positive squares in only one way, i.e., 115297256374336 + 17037048739216 = 10737656^2 + 4127596^2 .
It is a super-2 number, since 2×1323343051135522 (a number of 29 digits) contains 22 as substring.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 4135447034783 + ... + 4135447034814.
Almost surely, 2132334305113552 is an apocalyptic number.
It is an amenable number.
132334305113552 is a deficient number, since it is larger than the sum of its proper divisors (124063411043986).
132334305113552 is an equidigital number, since it uses as much as digits as its factorization.
132334305113552 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 8270894069605 (or 8270894069599 counting only the distinct ones).
The product of its (nonzero) digits is 486000, while the sum is 41.
Adding to 132334305113552 its reverse (255311503433231), we get a palindrome (387645808546783).
The spelling of 132334305113552 in words is "one hundred thirty-two trillion, three hundred thirty-four billion, three hundred five million, one hundred thirteen thousand, five hundred fifty-two".
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