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132340001231003 is a prime number
BaseRepresentation
bin11110000101110011001110…
…110000110101000010011011
3122100120120200020011020121012
4132011303032300311002123
5114321224310303343003
61145244053545204135
736606151413041006
oct3605631660650233
9570516606136535
10132340001231003
1139193096664205
1212a1446679064b
1358ac7bb03bac7
14249740c59c53d
1510477018b18d8
hex785ccec3509b

132340001231003 has 2 divisors, whose sum is σ = 132340001231004. Its totient is φ = 132340001231002.

The previous prime is 132340001230973. The next prime is 132340001231017. The reversal of 132340001231003 is 300132100043231.

It is a strong prime.

It is an emirp because it is prime and its reverse (300132100043231) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 132340001231003 - 222 = 132339997036699 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 132340001231003.

It is not a weakly prime, because it can be changed into another prime (132340001239003) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66170000615501 + 66170000615502.

It is an arithmetic number, because the mean of its divisors is an integer number (66170000615502).

Almost surely, 2132340001231003 is an apocalyptic number.

132340001231003 is a deficient number, since it is larger than the sum of its proper divisors (1).

132340001231003 is an equidigital number, since it uses as much as digits as its factorization.

132340001231003 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1296, while the sum is 23.

Adding to 132340001231003 its reverse (300132100043231), we get a palindrome (432472101274234).

The spelling of 132340001231003 in words is "one hundred thirty-two trillion, three hundred forty billion, one million, two hundred thirty-one thousand, three".