Base | Representation |
---|---|
bin | 11110000101110011001110… |
… | …110000110101000011001011 |
3 | 122100120120200020011020122222 |
4 | 132011303032300311003023 |
5 | 114321224310303343201 |
6 | 1145244053545204255 |
7 | 36606151413041105 |
oct | 3605631660650313 |
9 | 570516606136588 |
10 | 132340001231051 |
11 | 39193096664249 |
12 | 12a1446679068b |
13 | 58ac7bb03bb33 |
14 | 249740c59c575 |
15 | 10477018b191b |
hex | 785ccec350cb |
132340001231051 has 2 divisors, whose sum is σ = 132340001231052. Its totient is φ = 132340001231050.
The previous prime is 132340001231017. The next prime is 132340001231101. The reversal of 132340001231051 is 150132100043231.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-132340001231051 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 132340001231051.
It is not a weakly prime, because it can be changed into another prime (132340001231351) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66170000615525 + 66170000615526.
It is an arithmetic number, because the mean of its divisors is an integer number (66170000615526).
Almost surely, 2132340001231051 is an apocalyptic number.
132340001231051 is a deficient number, since it is larger than the sum of its proper divisors (1).
132340001231051 is an equidigital number, since it uses as much as digits as its factorization.
132340001231051 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2160, while the sum is 26.
Adding to 132340001231051 its reverse (150132100043231), we get a palindrome (282472101274282).
The spelling of 132340001231051 in words is "one hundred thirty-two trillion, three hundred forty billion, one million, two hundred thirty-one thousand, fifty-one".
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