Base | Representation |
---|---|
bin | 11110000101110011010001… |
… | …010000111011011010011010 |
3 | 122100120120210011010111110012 |
4 | 132011303101100323122122 |
5 | 114321224402024401104 |
6 | 1145244102044521522 |
7 | 36606152432550026 |
oct | 3605632120733232 |
9 | 570516704114405 |
10 | 132340043200154 |
11 | 3919310831a259 |
12 | 12a144788502a2 |
13 | 58ac7c6944a1a |
14 | 2497413da5386 |
15 | 1047705401d6e |
hex | 785cd143b69a |
132340043200154 has 16 divisors (see below), whose sum is σ = 198953458699392. Its totient is φ = 66022387220208.
The previous prime is 132340043200087. The next prime is 132340043200193. The reversal of 132340043200154 is 451002340043231.
It is a super-3 number, since 3×1323400432001543 (a number of 43 digits) contains 333 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 132340043200154.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 39277709 + ... + 42513744.
It is an arithmetic number, because the mean of its divisors is an integer number (12434591168712).
Almost surely, 2132340043200154 is an apocalyptic number.
132340043200154 is a deficient number, since it is larger than the sum of its proper divisors (66613415499238).
132340043200154 is an equidigital number, since it uses as much as digits as its factorization.
132340043200154 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 81793261.
The product of its (nonzero) digits is 34560, while the sum is 32.
Adding to 132340043200154 its reverse (451002340043231), we get a palindrome (583342383243385).
The spelling of 132340043200154 in words is "one hundred thirty-two trillion, three hundred forty billion, forty-three million, two hundred thousand, one hundred fifty-four".
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